(n+3)/(n^2+3n)

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Solution for (n+3)/(n^2+3n) equation: 


D( n )

n^2+3*n = 0

n^2+3*n = 0

n^2+3*n = 0

n^2+3*n = 0

DELTA = 3^2-(0*1*4)

DELTA = 9

DELTA > 0

n = (9^(1/2)-3)/(1*2) or n = (-9^(1/2)-3)/(1*2)

n = 0 or n = -3

n in (-oo:-3) U (-3:0) U (0:+oo)

(n+3)/(n^2+3*n) = 0

n^2+3*n = 0

n*(n+3) = 0

n+3 = 0 // - 3

n = -3

n*(n+3) = 0

(n+3)/(n*(n+3)) = 0

n+3 = 0 // - 3

n = -3

n in { -3} 

n belongs to the empty set

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